0.3x^2-7x=0

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Solution for 0.3x^2-7x=0 equation:



0.3x^2-7x=0
a = 0.3; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·0.3·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*0.3}=\frac{0}{0.6} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*0.3}=\frac{14}{0.6} =23+0.2/0.6 $

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